0=3w+2w^2-90

Solution for 0=3w+2w^2-90 equation:

0=3w+2w^2-90

We move all terms to the left:

0-(3w+2w^2-90)=0

We add all the numbers together, and all the variables

-(3w+2w^2-90)=0

We get rid of parentheses

-2w^2-3w+90=0

a = -2; b = -3; c = +90;
Δ = b2-4ac
Δ = -32-4·(-2)·90
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-27}{2*-2}=\frac{-24}{-4}
=+6
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+27}{2*-2}=\frac{30}{-4}
=-7+1/2
$